.:HSTuners::::Hondas Wanted:: |
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#19 |
Registered User
Join Date: Aug 2004
Location: West Coast
Age: 38
Posts: 2,244
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I agree with it being 1 and I verified it twice.
If you make the leading terms positives by taking +1 out of each of those negatives: (-1)(2y-5)(-1)(4y+3)(-1)(3y+2)(-1)(y-3) ---------------------------------------------- (3y+2)(2y-5)(4y+3)(y-3) Remove common terms: (-1)(-1)(-1)(-1) = 1 Then if you check the answer with y=0 (8y^2-14y-15) (3y^2-7y-6) ------------------ * ---------------- (6y^2-11y-10) (4y^2-9y-9) (-15) (-6) 90 ------ * ------- = ---- = 1 (-10) (-9) 90 Double check it with y=1 (8y^2-14y-15) (3y^2-7y-6) ------------------ * ---------------- (6y^2-11y-10) (4y^2-9y-9) (8-14-15) (3-7-6) ------------ * ----------- (6-11-10) (4-9-9) (-21) (-10) 210 ------ * ------- = ------ = 1 (-15) (-14) 210 I know my answer is a tad late, I haven't been getting to all of the boards lately. If you have other questions, feel send it my way. ![]()
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