I agree with it being 1 and I verified it twice.
If you make the leading terms positives by taking +1 out of each of those negatives:
(-1)(2y-5)(-1)(4y+3)(-1)(3y+2)(-1)(y-3)
----------------------------------------------
(3y+2)(2y-5)(4y+3)(y-3)
Remove common terms:
(-1)(-1)(-1)(-1) = 1
Then if you check the answer with y=0
(8y^2-14y-15) (3y^2-7y-6)
------------------ * ----------------
(6y^2-11y-10) (4y^2-9y-9)
(-15) (-6) 90
------ * ------- = ---- = 1
(-10) (-9) 90
Double check it with y=1
(8y^2-14y-15) (3y^2-7y-6)
------------------ * ----------------
(6y^2-11y-10) (4y^2-9y-9)
(8-14-15) (3-7-6)
------------ * -----------
(6-11-10) (4-9-9)
(-21) (-10) 210
------ * ------- = ------ = 1
(-15) (-14) 210
I know my answer is a tad late, I haven't been getting to all of the boards lately. If you have other questions, feel send it my way.
